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class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        # Solution 1
        if len(s) != len(t):
            return False
        for i in set(s):
            if s.count(i) != t.count(i):
                return False
        return True

    def isAnagram1(self, s: str, t: str) -> bool:
        # Solution 2
        if len(s) != len(t):
            return False
        dict_s, dict_t = {}, {}
        for i in range(len(s)):
            dict_s[s[i]] = dict_s.get(s[i], 0) + 1
            dict_t[t[i]] = dict_t.get(t[i], 0) + 1
        return dict_t == dict_s

    def isAnagram2(self, s: str, t: str) -> bool:
        # Solution 3
        from collections import Counter

        return Counter(s) == Counter(t)